diff pa-STP6N60M2.asc @ 17:f0665f53b854

Show FET power dissipation, don't bother with mod rail
author Daniel O'Connor <darius@dons.net.au>
date Sun, 19 Nov 2023 17:59:58 +1030
parents 1c4ff82b5704
children
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--- a/pa-STP6N60M2.asc	Sun Nov 19 17:36:45 2023 +1030
+++ b/pa-STP6N60M2.asc	Sun Nov 19 17:59:58 2023 +1030
@@ -225,8 +225,8 @@
 SYMBOL AutoGenerated/ISL55110 416 912 R0
 WINDOW 3 161 133 Top 2
 SYMATTR InstName U12
-TEXT 1440 576 Left 2 !.tran 0 440n 240n\n*.tran 0 1.8u 1.7u\n*.tran 0 5u 1.7u\n*.tran 0 2.5u 1.5u\n*.tran 0 5u
+TEXT 1440 576 Left 2 !*.tran 0 440n 240n\n*.tran 0 1.8u 1.7u\n.tran 0 5u 1.7u\n*.tran 0 2.5u 1.5u\n*.tran 0 5u
 TEXT 880 968 Left 2 !.meas PIN_HV AVG abs(V(HV)*I(V4))\n.meas PIN_MOD AVG abs(V(MOD_RAIL)*I(V2))\n.meas PIN_LV AVG abs(V(VCC)*I(V1))\n.meas POUT AVG abs(V(RFOut)*I(R1))\n.meas Efficiency Param 100*POUT/(PIN_HV + PIN_LV + PIN_MOD)\n.meas IPEAK_U2 max(abs(Ix(U2:D)))\n.meas V_IPEAK_U2 FIND abs(V(SW)) WHEN Ix(U2:D) = IPEAK_U2 * 0.999 cross=1\n.meas VPEAK_U2 max(abs(V(SW)))\n.meas I_VPEAK_U2 FIND abs(Ix(U2:D)) WHEN V(SW) = VPEAK_U2 * 0.999 cross=1
 TEXT 1448 696 Left 2 !.param F0 = 35.24Meg\n.param Tperiod = 1 / {F0}\n.param dutypct = 34\n.param Ton = 1 / {F0} * {dutypct} / 100\n.param C1 = 220p\n.param C2 = 230p\n.param L1 = 130n\n.param L2 = 178n\n.param R1 = 50
 TEXT 1448 904 Left 2 !.fourier {F0} 9 -1 V(rfout)
-TEXT 488 1112 Left 2 !*.step param dutypct 20 60 7\n*.step param C1 10p 300p 10p\n*.step param C2 80p 300p 5p\n.step param L2 80n 300n 15n
+TEXT 488 1112 Left 2 !*.step param dutypct 20 60 7\n*.step param C1 10p 300p 10p\n*.step param C2 80p 300p 5p\n*.step param L2 80n 300n 15n